Math 3118, Section 3

Spring 2001

Thursday, April 26 class handout

Class exercises

  1. Exercises from the text:

  2.  
  3. Supplementary exercise #1
    • One thousand left handed students and one thousand right handed students took a test. For the left handed students, the mean score was 75, and for the right handed students the mean score was 72.
       
    • Assume that the standard deviation was 4 points for the left-handed students and 6 points for the right-handed students. Determine how many left-handed students and how many right-handed students had scores:
      1. 80 or above
      2. 85 or above
      3. 90 or above
      4. 70 or below
      5. 65 or below
      6. 60 or below

      7.  
      Suggestions: As in the exercises in the text, you need to subtract the mean from the score in question (after shifting appropriately by 1/2) and then divide by the standard deviation in order to get the z-value.
      For instance: If we're considering left-handed students, then for scores of 80 or above we subtract the mean (=75) from 79.5 to get a difference of 4.5 points. To find the z-value, we divide this difference by the standard deviation (=4), obtaining 1.125 standard deviation units. Thus, z is about 1.1.
      Now, A(z) gives the area under the normal curve between 0 and z. We need the area under the curve which is to the right of z, so we take note of the fact that the total area under the right half of the normal curve is .5 and proceed accordingly. (¿¿Should we add or subtract??)
       


 

Homework due Tuesday, May 1

  1. Supplementary exercise #2
     
  2. Supplementary exercise #3
  3. = Exercise 11.4.1 from the text
     
  4. = Exercise 11.4.5 from the text
    Note:In this exercise, the phrase "within  z standard deviation units of the mean" indicates that we are looking for a region that includes areas on  both sides of the mean. After finding the value of  A(z) ¿¿what else do we have to do in order to find the desired area??
     

   

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