Math 5-335     Fall 2004
Hints and supplementary exercises for the October 21 homework

Supplementary problem #1   Consider the triangle shown in the following figure:

         

  1. Find the barycentric coordinates of the incenter, and then find the rectangular coordinates of the incenter.
  2. Find the point of the segment    that is closest to the incenter, and find the inradius (radius of the inscribed circle).
  3. Then find the points of the segments    and    that are closest to the incenter. Label all 3 of these points of tangency on a copy of the diagram.
  4. Find the points where the angle bisectors cross the opposite sides of the triangle, and label all 3 of these points on the same copy of the diagram that you used in part c.
      

Hint for §3.12, problem 64   Here's a diagram of the setup:

According to the plan presented in the text   we're given that   D   and   E   are on the line k   through   C   parallel to and further that   A   and   D are on opposite sides of   while   B   and   E   are on opposite sides of . Under this setup, we need to prove that and are opposite rays, so that we can apply Proposition 34 of Chapter 1 [about complementary angles]. We can reformulate the question about opposite rays as being about whether   D - C   and   E - C   are negative scalar multiples of each other. Since we're given that   k   is parallel to   ,   it is possible to compare either   D - C   or   E - C   with   B - A,   determining in each case whether the vector in question is a scalar multiple of   B - A,   with a positive coefficient or with a negative coefficient.

Now, the text says that the only other loose end is about showing that   A   and   B are on the same side of   k.   Actually, in the application of Proposition 33 of Chapter 1 [about addition of angular measure], one needs to check that   A   is in the interior of angle   BCE.   Showing that   A   and   B are on the same side of   k   is part of this, but not the whole story.   Indeed, it also involves showing that   A   and   E are on the same side of   .   What was proved about oppositeness of rays in the other part of the problem can be very helpful here.
 


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